Derive the relationship for the effective resistance of a circuit in s

1.	Derive the relationship for the effective resistance of a circuit in series with neat diagram
Answer» Two resistors of resistance R1\xa0and R2\xa0are connected in series. Let I be the current through the circuit. The current through each resistor is also I. The two resistors joined in series is replaced by an equivalent single resistor of resistance R such that the potential difference V across it, and the current I through the circuit remains same.\xa0As , V = IR , V1 =\xa0IR1 ,\xa0V2 =\xa0IR2\xa0 IR = IR1 +\xa0IR2\xa0 IR = I (R1\xa0+ R2)

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