Determime the AP whose third term is 16 and 7 th term exceed the 5th t

1.	Determime the AP whose third term is 16 and 7 th term exceed the 5th term by 12
Answer» An=a+(n-1)d So, 16=a+2d(equ1). , A7 =a+6d, A5= a+4d Now, according to statement we have, a+6d=a+4d+12 solving this equation we get. d=6 putting this value in( equ 1) we get a=4. Now we have a.=4 ,d= 6 so AP will be 4,10, 16 ,22 ,28.............

Discussion