Determine k in which 3k-2 ,4k-6 and k+2 are consecutive term of ap

1.	Determine k in which 3k-2 ,4k-6 and k+2 are consecutive term of ap
Answer» 4k-6-(3k-2)=k+2-(4k+6). {Common difference is equal coz its an Ap}4k-6-3k+2=k+2-4k-6k-4=3k-44k=0k=0 O 4k-6-(3k-2)=k+2-(4k-6)

Discussion