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Determine the ap whose third term is 16 and 7th term exceeds the 5th term by 12

Answer» A3 = 16A7 - A5 =12A+6d -A+4d =12By elimination:-2d =12D = 12/2D=6 answerHope it helps.....
A3 = 16 A7 - A5 = 12


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