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Determine the nature of the roots of the equation 2x^2+x-1 |
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Answer» D=b^2-4ac =(1)^2-4 (2)(-1) =1+8 =9D <9.: there exist real and distinct roots... Discriminant = b^2 - 4ac = (1) ^2 - 4 * -1 * 2 = 1 + 8 = 9. Therefore, the roots are REAL and DISTINCT in nature. |
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