1.

determine the ratio in which the line 3 X + Y =9 line segment joining the point (1,3)and (2,7).

Answer» Let the ratio be k:1Applying section formula,x = (2k+1/k+1) , and ,y = (7k+3/k+1)Therefore , 3x + y = 93(2k+1/k+1) + (7k+3/k+1) = 9(6k+3/k+1) + (7k+3/k+1) = 96k+3+7k+3/k+1 = 913k+6/k+1 = 913k+6 = 9k+94k = 3k = 3/4Therefore, the required ratio = 3:4
Let it divides it in the ratio m:n and coordinates of intersection is x,y Now find x and y in terms of m and n by the help of section form. and then put the val. on the line seg. you will get the ratio.?????????????????????
Sol. It
3:4


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