1.

Differentiate `log(secx+tanx)`with respect to `x`:

Answer» Let y=log (sec x + tan x)
`rArr (dy)/(dx)log (sec x +tan x) `
`1/(sec x+tan x ).(d)/(dx)(sec x tan x )`
`1/(sec x+tan x ).(d)/(dx)(sec x tan x +sec ^2 x )`
`=(sec x(tan x+ sec x))/(secx + tan x )=sec x.`


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