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1. |
Differentiate `log(secx+tanx)`with respect to `x`: |
Answer» Let y=log (sec x + tan x) `rArr (dy)/(dx)log (sec x +tan x) ` `1/(sec x+tan x ).(d)/(dx)(sec x tan x )` `1/(sec x+tan x ).(d)/(dx)(sec x tan x +sec ^2 x )` `=(sec x(tan x+ sec x))/(secx + tan x )=sec x.` |
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