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Differentiate `sqrt((x+1)(x+2)(x+3))` with respect to x. |
Answer» Let y=`sqrt((x+1)(x+2)(x+3))` `rArrlogy=log[sqrt((x+1)(x+2)(x+3))]` `=1/2log[(x+1)(x+2)(x+3)]` `=1/2[log(x+1)+log(x+2)+log(x+3)]` Differentiate both sides with sides with respect to x `1/y(dy)/(dx)=1/2[1/(x+1)+1/(x+2)+1/(x+3)]` `rArr(dy)/(dx)=1/2y(1/(x+1)+1/(x+2)+1/(x+3))` `=1/2sqrt((x+1)(x+2)(x+3))` `(1/(x+1)+1/(x+2)+1/(x+3))`. Ans |
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