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Differentiate the following function with respect to x :\(f(x)=\) \(tan^{-1}(\frac{1-x}{1+x})-\)\(tan^{-1}(\frac{x+2}{1-2x})\). |
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Answer» \(f(x)=\) \(tan^{-1}(\frac{1-x}{1+x})-\)\(tan^{-1}(\frac{x+2}{1-2x})\) \(=tan^{-1}(\frac{1-x}{1+x.1})-\) \(tan^{-1}(\frac{x+2}{1-2.x})\) = (tan-11 - tan-1x) - (tan-1x +tan-12) ( ∵ \(tan^{-1}\frac{a-b}{1+ab}=\)tan-1a - tan-1b) Differentiating with respect to x, we get f'(x) = \(-\frac{2}{1+x^2}\) |
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