Differentiate w.r.t. x the function`sin^3x+cos^6x` – InterviewSolution

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1.	Differentiate w.r.t. x the function`sin^3x+cos^6x`
Answer» Let `y=sin^(3)x+cos^(6)x` `implies(dy)/(dx)=(d)/(dx)(sin^(3)x+cos^(6)x)` `=(d)/(dx)(sinx)^(3)+(d)/(dx)(cosx)^(6)` `=3 (sinx)^(2)(d)/(dx)(sinx)+6(cos x)^(5)(d)/(dx)(cos x)` `=3sin^(2)x cos x-6 cos^(5)xsinx` `=3sin x cos x(sinx-2cos^(4)x)`

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