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Differentiate w.r.t. x the function `(sinx-cosx)^((sinx-cosx)),pi/4 < x < (3pi)/4` |
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Answer» `y = (sinx-cosx)^(sinx-cosx)` Taking log both sides, `logy = (sinx-cosx)log(sinx-cosx)` Now, differentiating both sides, `1/ydy/dx = log(sinx-cosx)(cosx+sinx)+ (sinx-cosx)*1/(cosx-sinx)*(cosx+sinx)` `1/ydy/dx = (cosx+sinx)(log(sinx-cosx)+1)` Putting value of `y` `dy/dx = (sinx-cosx)^(sinx-cosx) ((cosx+sinx)(log(sinx-cosx)+1))` |
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