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Distance between the point p(a+b, a-b) q(a-b, a+b)

Answer» Let distance between joining of two points (x1,y1) and (x2, y2)= √(x2-x1)²+(y2-y1)²(x1,y1) = P(a+b ,a-b)(x2, y2) = Q(a-b, a+b)PQ =√[a-b -(a+b)]²+ [a+b-(a-b)]²= √(a-b-a-b)²+ (a+b-a+b)²=√(-2b)²+ (2b)²=√4b²+4b²=√8b²=√(2*2)*2*b*b=2b√2
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