Divide 24 in 3 parts such that they are in AP and their product is 440

1.	Divide 24 in 3 parts such that they are in AP and their product is 440 ??
Answer» Solution:-Let the required terms of the given AP be a-d, a and a+d Where the first term is a-dThe common difference = dGiven : The sum of the three parts = 24∴ (a-d)+(a)+(a+d) = 243a = 24 #a = 8#Given : The product of these three terms = 440∴ (a-d) (a) (a+d) = 440#(8-d) (8) (8+d) = 440#- 8d² + 512 = 440#- 8d² = 440 - 512#- 8d² = - 72#d² = 72/8#d² = 9#d = √9#d= 3#So the three required terms of AP is 8 - 3 = 5 ; 8 and 8 + 3 = 11Three terms are 5, 8, 11

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