divide 24 in three parts such that they are in AP and their product is

1.	divide 24 in three parts such that they are in AP and their product is 440
Answer» The parts are in AP, let the terms be a-d, a and a+dwhere the first term =a-dthe common difference =dGiven, sum =24cma-d + a+a +d = 24cm3a = 24cma =8cmGiven: Product of the terms = 440(a-d) (a) (a+d) = 440(8-d) (8+d) (8) =440(8-d)(8+d) = 5582\xa0-d2\xa0= 5564 - d2\xa0= 55d2\xa0= 64-55d2\xa0= 9d = 3 or -3AP- a-d , a, a+dso the AP is 8-3, 8, 8+3 or 8+3,8,8-3AP = 5, 8, 11 or 11, 8, 5

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