Divide 27 into two parts such that the sum of their reciprocal is 3/20

1.	Divide 27 into two parts such that the sum of their reciprocal is 3/20
Answer» Let two parts be x and y So, x+y = 27 (1)A2q 1/x + 1/ y = 3/20 y+x/xy= 3/20 27/xy = 3/20 {from (1) } 3xy = 540 y = 540/3x y= 180/x (2)Substituting y= 180/x in eqn (1) x+180/x = 27 x^ +180/x =27 x^ + 180 =27x x^ -27x+180= 0 x^ - (12 + 15) x + 180 =0 x^ - 12x - 15x + 180 = 0 x (x- 12) - 15 (x -12) =0 ( x-15) (x-12) =0 Either, Or x=15 x =12 Therefore two parts are 15 and 12 HOPE IT HELPS YOU

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