InterviewSolution
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InterviewSolution
| 1. |
Divide 39 into two parts such that their product is 324.A question from quadratic equation. |
| Answer» {tex}\\large Solution:{/tex}\t\xa0{tex}\\large Let \\space \'a\'\\space\\space and\\space \'b\'\\space be\\space the\\space two\\space numbers.{/tex}{tex}\\large Thus,\\begin{cases} \\ \\\\ \\ \\\\ \\ \\end{cases}{/tex}\xa0{tex}\\Large a+b=39 \\dots (i)\\\\\\Large a\\times b=324\\dots(ii){/tex}{tex}\\large Putting \\space b=39-a\\space in\\space the\\space eq.\\space(ii)\\space,we\\space get{/tex}{tex}\\Large \\implies a\\times b=324\\\\\\Large \\implies a\\times (39-a)=324\\\\\\Large \\implies39a-a^2=324\\\\\\Large \\therefore a^2-39a+324=0\\\\ \\space\\\\\\Large \\therefore a=12,\\space 27.{/tex}\xa0{tex}\\huge a{/tex}{tex}\\huge b{/tex}{tex}\\huge a+b{/tex}{tex}\\huge a\\times b{/tex}{tex}\\huge 12{/tex}{tex}\\huge 27{/tex}{tex}\\huge 39{/tex}\xa0{tex}\\huge 324{/tex}\xa0{tex}\\huge 27{/tex}\xa0{tex}\\huge 12{/tex}\xa0{tex}\\huge 39{/tex}\xa0{tex}\\huge 324{/tex}\xa0\t | |