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Draw a line segment AB= 7cm.Take a point P on AB such that AP:PB= 3:4

Answer» Steps of construction:\tDraw a line segment AB = 7 cm}\tDraw a ray AX making an acute angle BAX with AB\tAlong AX mark (3 + 5) = 8 points.\tA1, A2, A3, A4, A5, A6, A7, A8\tsuch that AA1\xa0=\xa0A1A2\xa0= A2A3\xa0= A3A4\xa0= A4A5\xa0= A5A6\xa0= A6A7\xa0= A7A8\tJoin A8B.\tThrough the point A3, draw a line parallel to A8B by making an angle equal to\xa0{tex}\\angle{/tex}AA8B at A3.Suppose this line meets AB at a point P.Thus, P is the required point such that\xa0{tex}\\frac { A P } { P B } = \\frac { 3 } { 5 }{/tex}.


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