End term of A.p:17,14,11..-40

1.	End term of A.p:17,14,11..-40
Answer» A.P. is 17,14,11,..., - 40We have,l = Last term = -40 , a = 17 and, d = Common difference= 14 - 17 = - 3{tex}\\therefore{/tex}\xa06th term from the end = l - (n -1)d=\xa0l - (6-1) d= -40 - 5 {tex}\\times{/tex} (-3 )= -40 + 15= -25So, 6th term of given A.P. is -25.

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