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Estrification and saponification reaction |
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Answer» When a carboxylic acid is treated with an alcohol and an acid catalyst, an ester is formed (along with water). This reaction is called the Fischer esterification.✔️Saponification:Esters react in the presence of an acid or a base to give back the alcohol and carboxylic acid. This is called saponification reaction. This is reverse reaction of esterification reaction.\xa0CH3COOC2H5 + NaOH →\xa0CH3-COOH + CH3-CH2-OH Esterification: The reaction between Acid and an Alcohol to produce ester as the product is called Esterification reaction. During this reaction a molecule of water is eliminated.Ex: CH₃COOH + C₂H₅OH →CH₃COOC₂H₅ + H₂OIn the above reaction Ethanoic acid reacted Ethyl alcohol to form an ester Ethyl Acetate and water molecule.Saponification: Esters react in the presence of an acid or a base to give back the alcohol and carboxylic acid. This is called saponification reaction. This is reverse reaction of esterification reaction.CH3COOC2H5 + NaOH →\xa0CH3-COOH + CH3-CH2-OH |
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