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| 1. |
Evaluate 2cos67°/sin23°-tan40°\\cot50°-cos0° |
| Answer» {tex}\\begin{array}{l}=\\frac{2\\cos67^o}{\\sin23^o}-\\frac{\\tan{\\displaystyle{\\displaystyle40}^{{}^o}}}{cot50^o}-\\cos0^o\\\\=\\frac{2\\sin(90-67)}{\\sin{\\displaystyle23}}-\\frac{cot(90-40}{cot50}-1\\\\=\\frac{2\\sin23}{\\sin{\\displaystyle23}}-\\frac{cot50}{cot50}-1\\\\=2-1-1\\\\=2-2\\\\=0\\end{array}{/tex} | |