Evaluate `(72.3)^(1/3); if `log 0.723=bar(1).8591`

1.	Evaluate `(72.3)^(1/3); if `log 0.723=bar(1).8591`
Answer» Let `root(3)72.3`. Then ` log x = log(72.3)^(1//3)` ` or log x = 1/3 log 72.3` ` or log x = 1/3 xx 1.8591` ` rArr log x = 0.6197` ` or x = "antilog "` (0.6197)` ` = 4.166 ` (using antilog table)

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