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Evaluate..cot12°cot38°cot52°cot60°cot78° |
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Answer» 1/root3 cot12cot38cot52cot60cot78=cot(90-78)cot(90-52)cot52cot60cot78=tan78cot78 x tan52cot52 x cot60=1x1x1 x cot60={tex}\\frac{1}{\\sqrt3}{/tex} 1/√3 1/√3 |
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