1.

Evaluate `int_-1^ 1 sin^5xcos^4xdx`

Answer» Here,` f(x) = int_-1^1sin^5xcos^4xdx`
If we find, `f(-x)`,
`f(-x) = int_-1^1sin^5(-x)cos^4(-x)dx`
`=int_-1^1-sin^5xcos^4xdx=-int_-1^1sin^5xcos^4xdx`
`=-f(x)` that means f(x) is an odd function.
We know, `int_-a^af(x)dx = 0`, if f(x) is an odd function. Thus,`int_-1^1sin^5xcos^4xdx = 0`


Discussion

No Comment Found