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Evaluate `int(dx)/((x^(2)+6x+13))`.

Answer» We have `int(dx)/((x^(2)+6x+13))=int(dx)/({(x^(2)+6x+9)+4})`
`=int(dx)/({(x+3)^(2)+2^(2)})=int(dt)/((t^(2)+2^(2)))`, where `(x+3)=t`
`=(1)/(2)"tan"^(-1)(t)/(2)+C`
`=(1)/(2)"tan"^(-1)(1)/(2)(x+3)+C`.


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