`int(x^(2))/((x^(2)+6x-3))dx`

1.	`int(x^(2))/((x^(2)+6x-3))dx`
Answer» Correct Answer - `x-3log\|x^(2)+6x-3\|+(7sqrt(3))/(4)log\|(x+3-2sqrt(3))/(x+3+2sqrt(3))\|+C` On dividing `x^(2)` by `(x^(2)+6x-3)` , we get `I=int{1-(6x-3)/(x^(2)+6x-3)}dx=x-3int((2x-1))/((x^(2)+6x-3))dx`. Let `(2x-1)=A*(d)/(dx)(x^(2)+6x-3)+BrArr(2x-1)=A(2x+6)+B`.

Discussion

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