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Evaluate `int (dx)/(xsqrt(x^6-1))` |
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Answer» Put `x^(3)=t` so that `3x^(2)dx=dt" or "x^(2)dx=(1)/(3)dt`. `:.int(dx)/(x*sqrt(x^(6)-1))dx` [multiplying numerator and denominator by `x^(2)]` `=(1)/(3)int(1)/(tsqrt(t^(2)-1))dt=(1)/(3)sec^(-1)t+C=(1)/(3)sec^(-1)t+C=(1)/(3)sec^(-1)x+C`. |
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