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Evaluate:`int1/(sqrt(x)+x)dx` |
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Answer» `int(1)/((sqrt(x)+x))dx=int(1)/(sqrt(x)(1+sqrt(x)))dx` Now, put `(1+sqrt(x))` =t so that `(1)/(sqrt(x))dx=2dt`. `:.int(1)/(sqrt(x)+x)dx=int(1)/(sqrt(x)(1+sqrt(x)))dx` `=2intdt=2log|t|+C=2log|{:(1+sqrt(x)):}|+C`. |
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