InterviewSolution
Saved Bookmarks
| 1. |
Evaluate `root(3)(0.08034).` |
|
Answer» Let `x = root(3)(0.08034).` Then, log `x = 1/3` log (0.08034). `= 1/3 (bar(2).9049) = 1/3(-2 + 0.9049) = 1/3(-1.0951)` `= -0.3650 = -1 + (1 - 0.3650) = bar(1).6350` `rArr` x = antilog `(bar(1).6350) = 0.4315.` |
|