Saved Bookmarks
| 1. |
Evaluate:Sin^2 63°+ sin^2 27° ÷ cos^2 17°+cos^2 73° |
|
Answer» Thank u..☺ First of all I would make it clear thatSin(90-a)= cos a.So, sin^2 63°would be cos^2 17°and cos^2 17°=sin^2 73°In the expression given in the question,(Cos^2 17°+sin^2 17°)/(sin^2 73°+cos^2 73)Since sin^2 a+cos^2 a=1, it would become 1/1=1Hence, the answer is 1. Plz ans.. |
|