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Evaluate:`sin(cos^(-1)3/5+cos e c^(-1)(13)/5)`

Answer» `sin(cos^-1 (3/5) + cosec^-1(3/5))`
`= sin(cos^-1(3/5)) cos(cosec^-1(13/5)) + cos(cos^-1(3/5))sin(cosec^-1(13/5))`
`= sin (sin^-1(4/5)) cos(cos^-1(12/13)) + cos(cos^-1(3/5))sin(sin^-1(5/13))`
here, `cos theta = 3/5`
`sin theta = 4/5`
so, in equation
`=4/5 xx 12/13 + 3/5 + 5/13`
`= 4/65 + 15/65 = 63/65`
Answer


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