Prove that `tan(cot^(-1)x)=cot(tan^(-1)x)`

1.	Prove that `tan(cot^(-1)x)=cot(tan^(-1)x)`
Answer» `tan(cor^-1 x) = cot(tan^-1 x) ` `tan^-1 x + cot^-1 x = pi/2` `tan theta = cot(pi/2 - theta)` LHS: `tan(cot^-1 x) = cot(pi/2 - cot^-1 x)` `= cot(tan^-1 x) `=RHS hence proved

Discussion

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