Write the value of `cos^2(1/2cos^(-1)3/5)`

1.	Write the value of `cos^2(1/2cos^(-1)3/5)`
Answer» `cos 2 theta = 2cos^2 theta- 1` `=> cos^2 theta = (1 + cos 2 theta)/2` `cos^2 (1/2 cos^-1(3/5))` `= (1 + cos(2 xx 1/2 cos^-1 (3/5)))/2` `=> (1 + cos(cos^-1(3/5)))/2` `= (1 + (3/5))/2 = 8/(2 xx 5)` `= 4/5` Answer

Discussion

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