InterviewSolution
Saved Bookmarks
| 1. |
Write the value of `sin^-1(sin1550^@)` |
|
Answer» `1550^@ = 1550 xx pi/180` `= (155 pi)/18` `=> sin^-1(sin ((155 pi)/18))` `= sin^-1 (sin (8 pi + (11 pi)/18))` `=> sin^-1(sin((11pi)/18))` `= sin^-1[sin(pi- (7pi)/18)]` `=> sin^-1(sin((7pi)/18))= (7pi)/18` Answer |
|