1.

Write the value of `sin^-1(sin1550^@)`

Answer» `1550^@ = 1550 xx pi/180`
`= (155 pi)/18`
`=> sin^-1(sin ((155 pi)/18))`
`= sin^-1 (sin (8 pi + (11 pi)/18))`
`=> sin^-1(sin((11pi)/18))`
`= sin^-1[sin(pi- (7pi)/18)]`
`=> sin^-1(sin((7pi)/18))= (7pi)/18`
Answer


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