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| 1. |
Evaluate sin60° geometrically |
| Answer» We consider any right angled triangle ABDWe have base BD = a,Perpendicular AD = √ 3aHipotenuse AB = 2a andAngle ABD = 60•Sin60• = AD / AB = √3a /2a Sin 60• = √3/2May this will help full for you ....? | |