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Evaluate: `tan(2tan^(-1)(1/5))`

Answer» We have =`tan(2tan^-1 1/5) `
as `[2 tan^-1 x = tan^-1((2x)/(1-x^2))]`
so,`tan(tan^-1 ((2(1/5))/(1- (1/5)^2)))`
`= tan(tan^-1 (2/5 xx 25/24))`
`= 5/12`
Answer


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