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exercise 12.1 Q no. 3 anyone please i need only hint |
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Answer» thanks a lot Area of 1st region gold = πr^2 = 22/7 × 10.5 × 10.5 & Area of 2nd region red = π(R^2 - r^2) = 22/7 ×(21^2 - 10.5^2) & Area of 3rd region blue = π(R^2 - r^2) = 22/7 ×(31.5^2 - 21^2) Radius of gold =10.5 Area of gold = 22/7 × (10.5)^2Radius of red =10.5+10.5Area of red =22/7×(21)^2 - area of gold Similarly add 10.5 in radius for next and for its area 22/7×(21+10.5)^2 - 22/7×(21)^2 |
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