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Exercise 4.2 ques.no.6 ncert |
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Answer» 6. A cottage industry produces a certain number of pottery articles in a day. It was observed on a particular day that cost of production of each article (in rupees) was 3 more than twice the number of articles produced on that day. If, the total cost of production on that day was Rs. 90, find the number of articles produced and the cost of each article.Ans.\xa0Let cost of production of each article be Rs xWe are given total cost of production on that particular day = Rs 90Therefore, total number of articles produced that day = 90/xAccording to the given conditions,⇒⇒⇒⇒⇒⇒x\xa0(x\xa0− 15) + 12 (x\xa0− 15) = 0⇒(x\xa0− 15) (x\xa0+ 12) = 0⇒x\xa0= 15, −12Cost cannot be in negative, therefore, we discard\xa0x\xa0= −12Therefore,\xa0x\xa0=\xa0Rs\xa015 which is the cost of production of each article.Number of articles produced on that particular day =\xa0= 6 Hi |
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