Exercise 4.2 question number 2

1.	Exercise 4.2 question number 2
Answer» 2. Write four solutions for each of the following equations:(i) 2x+y = 7Solution:To find the four solutions of 2x+y =7 we substitute different values for x and yLet x = 0Then,2x+y = 7(20)+y = 7y = 7(0,7)Let x = 1Then,2x+y = 7(2×1)+y = 72+y = 7y = 7-2y = 5(1,5)Let y = 1Then,2x+y = 7(2x)+1 = 72x = 7-12x = 6x = 6/2x = 3(3,1)Let x = 2Then,2x+y = 7(2×2)+y = 74+y = 7y =7-4y = 3(2,3)The solutions are (0, 7), (1,5), (3,1), (2,3)(ii) πx+y = 9Solution:To find the four solutions of πx+y = 9 we substitute different values for x and yLet x = 0Then,πx+y = 9(π0)+y = 9y = 9(0,9)Let x = 1Then,πx +y = 9(π×1)+y = 9π+y = 9y = 9-(1, 9-)Let y = 0Then,πx+y = 9πx+0 = 9πx = 9x = 9/(9/,0)Let x = -1Then,πx + y = 9(×-1) + y = 9-+y = 9y = 9+π(-1,9+)The solutions are (0,9), (1,9-), (9/,0), (-1,9+)(iii) x = 4ySolution:To find the four solutions of x = 4y we substitute different values for x and yLet x = 0Then,x = 4y0 = 4y4y= 0y = 0/4y = 0(0,0)Let x = 1Then,x = 4y1 = 4y4y = 1y = 1/4(1,1/4)Let y = 4Then,x = 4yx= 4×4x = 16(16,4)Let y =Then,x = 4yx = 4×1x = 4(4,1)The solutions are (0,0), (1,1/4), (16,4), (4,1)

Discussion