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Exercise 9.1. Question 6

Answer» A 1.5 m tall boy is standing at some distance from a 30 m tall building. The angle of elevation from his eyes to the top of the building increases from\xa0\xa0to\xa0\xa0as he walks towards the building. Find the distance he walked towards the building.Ans.\xa0AB = 30 m and PR = 1.5 mAC = AB – BC= AB – PR= 30 – 1.5= 28.5 mIn right triangle ACQ,\xa0\xa0QC =\xa0\xa0mIn right triangle ACP,\xa0\xa0\xa0\xa0\xa0\xa0PQ =\xa0\xa0PQ =\xa0\xa0=\xa0\xa0mHence, the walked towards the building is\xa0\xa0m.


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