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Explain how the intensity of diffraction pattern changes as the order `(n)` of the diffraction bands. |
Answer» The diffraction pattern due to a single slit consists of a central bright maximum at `O` alingwith alternate secondary minima and maxima on either side. The intensity distribution on the screen is represented in Fig. 6(f).6. The secondary maxima ate the points in between secondary maxima and are of rapidly decreasing intensity. If `I_(0)` is intensity of central bright maximum, then intensity of first secondary maximum, is found to be `I_(0)//22`, and of second secondary maximum is `I_(0)//61` and so on. Note that intensity of central maximum is due to wavelets from all parts of the slit exposed to light. In the first secondary maximum, first two parts of the slit send wavelets in opposite phase, which cancel out. Therefore, intensity of 1st secondary maximum is due to wavelets from only one third part of slit. Similarly, the intensity of second secondary maximum is due to wavelets only from one fifth part of the slit, and so on. |
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