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| 1. |
Explain some one question without using pythagoras theroem |
| Answer» Let A (4, 4), B (3, 5) and C(-1, -1) be three vertices of a {tex}\\Delta {\\rm A}{\\rm B}C{/tex}.{tex}\\therefore{/tex}\xa0Slope of AB {tex} = \\frac{{5 - 4}}{{3 - 4}} = \\frac{1}{{ - 1}} = - 1{/tex}{tex}\\therefore{/tex}\xa0Slope of BC {tex}= \\frac{{ - 1 - 5}}{{ - 1 - 3}} = \\frac{{ - 6}}{{ - 4}} = \\frac{3}{2}{/tex}{tex}\\therefore{/tex}\xa0Slope of AC {tex} = \\frac{{ - 1 - 4}}{{ - 1 - 4}} = \\frac{{ - 5}}{{ - 5}} = 1{/tex}Now slope of AB {tex}\\times{/tex} slope of AC = -1{tex}\\times{/tex}1 = -1This shows thatAB{tex}\\bot{/tex}AC. Thus {tex}\\Delta {\\rm A}{\\rm B}C{/tex} is right angled at point A. | |