Express the HCF of 210 and 66 as 210x+66y, where x,y are integers

1.	Express the HCF of 210 and 66 as 210x+66y, where x,y are integers
Answer» Applying Division lemma on 210 and 66210=663+2-----------(1)Applying Division lemma on 2 and 6666=233+0Here remainder is zero\xa0so HCF(66,210)=2Now from(1)2=210-366HCF=2101-366-----------------(2)Given HCF=210x+66y-------------(3)Comparing (2) and (3) we getx=1 and y=-3Hence HCF=2101-3*66\xa0\xa0

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