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F(x)=x^2-4x+3Find:- alpha^4 beta^2+alpha^2beta^4 |
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Answer» α^4β^2+α^2β^4=α^2β^2(α^2+β^2)=(3)^2(10)=9(10)=90 αβ=3 α^2+β^2=10 Sorry Pehle galat type ho gaya Ans. 90 α+β=4αβ=3Then α^2+β^2=16We have to find α^4β^2+α^2β^4Taking α^2β^2 common Then, α^2β^2(α^2+β^2)(αβ)^2(α^2+β^2)=(3)^2(16)=9(16)=144 |
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