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Factories 4u² +8u |
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Answer» p(x) = 4u²+8u\xa04u ( u + 2 ) = 0[4u + 0 ] [ u + 2 ] ------> factorized formhence ,u = 0u = -2Here ,a = 4b = 8c = 0Relation between zeros and its coefficients :-Sum of zeroes = 0 + -2 = - 2\xa0= -b/a = -8/4 = -2Product of zeroes = 0 x -2 = 0\xa0= c/a = 0/4 = 0\xa0 4u{u+2} 2u[2u+4] 4u (u+2) |
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