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Factorise\xa0X2+2√2x-6\xa0 |
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Answer» Given expression=x2+2√2x-6 =x2+3√2x-√2x-6 =x(x+3√2)-√2(x+3√2) =(x+3√2)(x-√2) {tex}{x^2} + 2\\sqrt 2 x - 6{/tex}= {tex}{x^2} + 3\\sqrt 2 x - \\sqrt 2 x - 6{/tex}= {tex}x\\left( {x + 3\\sqrt 2 } \\right) - \\sqrt 2 \\left( {x + 3\\sqrt 2 } \\right){/tex}= {tex}\\left( {x + 3\\sqrt 2 } \\right)\\left( {x - \\sqrt 2 } \\right){/tex} √2,-3√2. |
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