Find 2 consecutive natural no. The sum of the whose squares is 145

1.	Find 2 consecutive natural no. The sum of the whose squares is 145
Answer» Solution: let first number = xThen second number = x +1ATQ,=> x2 + (x+1)2 = 145=> x2\xa0+ x2 +2x + 1\xa0= 145=> 2x2 +2x - 144= 0divide by 2=> x2 + x - 72 = 0 => x2 + 9x - 8x +72 = 0=> x(x+9) -8(x+9) = 0=> (x+9)(x-8)= 0=> x = 8, -9as x is natural number so -9 cannot be value of x.So numbers are 8,9.\xa0\xa0

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