Find 2 consecutive positive integers ,sum of whose squares is 925.

1.	Find 2 consecutive positive integers ,sum of whose squares is 925.
Answer» let first integer be xthen its consecutive integer be (x+1)according to questionx^2 + (x+1)^2 = 9252x^2 + 2x - 924 = 0x^2 + x - 462 = 0x = -1 +- √1 + 4*462 / 2x = -1 +- 43/2x = -1 + 43 /2 = 21x = -1 - 43/2 = -22x = 21 , -22

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