Find 3 consecutive positive integer whose product is equal to 16 times

1.	Find 3 consecutive positive integer whose product is equal to 16 times their sum
Answer» Let three consecutive numbers are x, x+1, x+2Then according to question\xa0X(x+1)(x+2)=x+x+1+x+2X(x\u200b\u200b\u200b\u200b\u200b\u200b2+3x+2)=3x+3X\u200b\u200b\u200b\u200b\u200b\u200b3+3x2+2x-3x-3=0(x-1)(x\u200b\u200b\u200b\u200b\u200b\u200b2+4x+3)=0(X-1)(x+3)(x+1)=0X=1, -3 ,-1-3 and -1 is not possible according to question .So 1,2,3 are three require consecutive possitive integer\xa0\xa0

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