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Find 31 st term of an AP whose 11 th term is 38 and 16 th term is 73 |
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Answer» {tex}\\eqalign{ & {t_{31}} = a + 30d \\cr & = - 32 + 30(7) \\cr & = 178 \\cr} {/tex} {tex}\\eqalign{ & Given\\,\\,that\\,:{t_{11}} = 38 \\cr & {t_{16}} = 73 \\cr & Let\\,first\\,term\\,be\\,a\\,and\\,common\\,difference\\,is\\,d \\cr & a + 10d = 38\\,\\,\\,\\,\\,\\,eq.\\left( 1 \\right) \\cr & a + 15d = 73\\,\\,\\,\\,\\,\\,\\,eq.(2) \\cr & eqs.(1)\\, - (2) \\cr & - 5d = - 35 \\cr & d = 7 \\cr & so\\,from\\,(1) \\cr & a = - 32 \\cr & {t_{38}} = a + 37d \\cr & = - 32 + 37(7) \\cr & = 227 \\cr & \\cr} {/tex} 178 |
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