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Find a cubic Polynomial whose zeroes are 3,5,-2 |
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Answer» Let α=3,β=5,gamma =-2 let the required polynomial be denoted by p(x) then solve accordingly Nice Here , sum of zeroes= 3+5+(-2)=8-2=6 Product of zeroes= 3*5*(-2)= -30Sum of product of zeroes taken at one time=(3)(5)+(5)(-2)+(-2)(3)=15-10-6=-1Thus, the equation formed is, x^3 -(6)x^2 +(-1)x - (-30)=x^3 -6x^2 -1 +30 |
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